doc: update docs/kotlin.md (#331)
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		@@ -606,6 +606,75 @@ fun main() {
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```
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### 简单的高阶函数
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```kotlin
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//注意啦,这里的num1AndNum2有个operation,它是接收了一个函数作为形参
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fun num1AndNum2(num1: Int, num2: Int, operation: (Int, Int) -> Int): Int {
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    //让我们试着向operation传入参数
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    return operation(num1, num2)
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}
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fun plus(num1: Int, num2: Int): Int {
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    return num1 + num2
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}
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fun main(args: Array<String>) {
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    val total = num1AndNum2(100, 200, ::plus)
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    println(total)//300
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    //怎么样?我们利用传入一个函数来充当另一个函数的参数
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}
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```
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还记得我们怎么在Java中用接口吗?
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试着用函数参数简化它
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### 以匿名函数作为参数的函数
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```kotlin
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//operation是一个函数类型的参数哦
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fun num1AndNum2(num1: Int, num2: Int, operation: (Int, Int) -> Int): Int {
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    return operation(num1, num2)
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}
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fun main(args: Array<String>) {
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    //这里我们定义一个匿名函数
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    val operation: (Int, Int) -> Int = { i: Int, i2: Int ->
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        i + i2
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    }
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    val total = num1AndNum2(100, 200, operation)
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    println(total) //300
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}
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```
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<!--rehype:className=wrap-text-->
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### Lambda表达式方式传入函数参数
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```kotlin
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//我们还是不改变什么
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fun num1AndNum2(num1: Int, num2: Int, operation: (Int, Int) -> Int): Int {
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    return operation(num1, num2)
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}
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fun main(args: Array<String>) {
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    //wow哦天哪,Lambda可以做到这样简洁
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    val total = num1AndNum2(100, 200) { n1, n2 ->
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        n1 + n2
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    }
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    println(total)
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}
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```
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这里之所以可以把lambda写在外部,是因为operation是最后一个参数。
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类
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---
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