doc: update neo4j.md (#638)
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		@@ -193,8 +193,53 @@ DELETE n
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MATCH (alice:Person {name: 'Alice'})-[:FRIENDS]->()-[:FRIENDS]->(fof)
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					MATCH (alice:Person {name: 'Alice'})-[:FRIENDS]->()-[:FRIENDS]->(fof)
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RETURN fof
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					RETURN fof
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// 查找共同朋友
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					// 查找共同朋友,这里的“,”相当于 AND 条件
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MATCH (alice:Person {name: 'Alice'})-[:FRIENDS]->(friend),
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					MATCH (alice:Person {name: 'Alice'})-[:FRIENDS]->(friend),
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      (bob:Person {name: 'Bob'})-[:FRIENDS]->(friend)
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					      (bob:Person {name: 'Bob'})-[:FRIENDS]->(friend)
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RETURN friend
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					RETURN friend
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```
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					```
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					通过观察`John的朋友`看过的电影为`John`推荐电影,并且不再推荐`John`他自己已经看过的电影。
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					```cypher
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					MATCH (tom:Person {name: "John Johnson"})-[:IS_FRIEND_OF]->(user)-[:HAS_SEEN]->(movie)
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					WHERE NOT tom-[:HAS_SEEN]->(movie) RETURN movie.name;
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					```
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					找出所有标题以`Apollo`开头且发行年份早于`1996`年的电影节点
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					```cypher
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					MATCH (node:Movie)
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					WHERE node.title =~ 'Apollo.*' AND node.released < 1996
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					RETURN node
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					```
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					### 排序&分页
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					以电影名字排序,每一网页只显示10部电影,下面的查询返回了第三页(21~30项)。
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					```cypher
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					match (alice:Person {name: 'Alice'})-[HAS_SEEN]->(movie) 
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					return movie 
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					order by movie.name 
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					skip 20 
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					limit 10
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					```
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					### 聚合函数
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					计算每一部电影被观看的数量,按数量排序
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					```cypher
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					 match (node:Movie)-[:HAS_BEEN_SEEN]->() 
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					return node,count(*) 
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					 order by count(*) desc;
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					```
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					要求`John`所有朋友的平均年龄,可以使用以下查询
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					```cypher
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					match (node:users{name: "John Johnson"})-[:IS_FRIEND_OF]-(friend) 
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					where HAS(friend.yearOfBirth) 
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					return avg(2014-friend.yearOfBirth);
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					```
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